Question

Challenge time: I have a fractional exponent problem (posted in the comments). Could I get a step by step?

Answer 1

\[\frac{ X ^{3/4}Y }{ XY ^{-1/2} }\]

Answer 2

\[\frac{x^{3/4}y}{xy^{-1/2}}\]

OK... put the \(y^{-1/2}\) in the numerator.

Answer 3

\(x^{-1} \iff \dfrac{1}{x}\) Therefore \(\dfrac{1}{x^{-1}} \iff \dfrac{x^1}{1}\)

Answer 4

This becomes \(\dfrac{x^{3/4}}{x^1} \cdot (y^1 \cdot y^{1/2})\)

Answer 5

Remember, \(x^m \cdot x^n = x^{m+n}\) where m and n are exponents, and x is the base function, or variable.

Answer 6

Another rule: \(\dfrac{x^{m}}{x^n} = x^{m-n}\)

Answer 7

ok

Answer 8

Try working it out with the given formulas, and i'll check your work :)

Answer 9

\[\frac{ y ^{3/4} }{ x ^{1/4} }\]

Answer 10

almost.

Answer 11

?

Answer 12

\[y^1 \cdot y^{1/2} = y^{2/2 + 1/2} = y^?\]

Answer 13

i wrote 3/2... and typed 3/4...

Answer 14

:)

Answer 15

its seriously been a day with these problems haha...

Answer 16

thank you for all your help :)

Answer 17

It's paid off though! You've got this :)

Answer 18

i sure hope so the test is tomorrow :) lol

Answer 19

Good luck! Do well :)