Question

Chapter 5:Indices and Logarithms
Solve the equation.
Double checking.
@ganeshie8

Answer 1

\[\log _{2}x+2=3\log _{x}2\]

Answer 2

\[\log _{2}x+2=3\frac{ 1 }{ \log _{2}x }\]

Answer 3

\[x+2=3\frac{ 1 }{ x }\]

Answer 4

\[x(x+2=3\frac{ 1 }{ x })\]

Answer 5

\[x^2+2x=3\]

Answer 6

hey let it be some other variable so that we wont get confused : \(\log_2 x = t\)

Answer 7

okay

Answer 8

\[t^2+2t=3\]

Answer 9

looks good :)

Answer 10

\[t^2+3t-t-3=0\]

Answer 11

\[t(t+3)-1(t+3)=0\]

Answer 12

\[t=1~and~t=-3\]

Answer 13

\[\log _{2}x=1\]\[\log _{2}x=-3\]

Answer 14

*

Answer 15

\[x=2^1,x=2^{-3}\]

Answer 16

Am i correct? @ganeshie8

Answer 17

Excellent work ! lets triple check wid wolf
http://www.wolframalpha.com/input/?i=solve+%5Clog_2+x%2B2%3D3%5Clog_x+2+over+reals

Answer 18

It says that x=2 and x=1/8 @ganeshie8

Answer 19

Thnx @ganeshie8

Answer 20

yw!