Question

how many molecules of dinitrogen pentoxide are present if there are 0.0543 g of oxygen atoms in the sample

Answer 1

@ribhu

Answer 2

u know dinitrogen pentoxide is N2O5, mol wt =108

Answer 3

yes

Answer 4

1 mol n2o5 contains 5 mol oxygen

Answer 5

yes

Answer 6

108 gm n2o5 contains 80 gm oxygen

Answer 7

so there is 28 grams of nitrogen

Answer 8

0.05423 mol of oxygen since gm atoms = mol

Answer 9

for this 1 mol oxygen would be contained in 1/5 mol n205
so .05423 mol ox we need to have 1/5 *.05423 mol n205

Answer 10

so the molecules of n2o5 are
1/5 *.05423 * 6.023*10^23 molecules

Answer 11

6.53*10^21 molecules of n2o5 @ryankean12 this would be the answer

Answer 12

i kinda get it just not the "for this 1 mol oxygen would be contained in 1/5 mol n205
so .05423 mol ox we need to have 1/5 *.05423 mol n205"

Answer 13

how did you get the 1/5 *.05423 mol N2O5?

Answer 14

see gram of atoms are same as moles

Answer 15

and we know 1 mol n2o5 has 5 mol oxygen
so 1 mol oxygen would be contained in 1/5 mol n2o5

Answer 16

i get it now

Answer 17

and hence from the question .05423 gram of oxygen atoms or mol of oxygen.

Answer 18

i hope i am clear now.

Answer 19

@ryankean12