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Geometry 14 Online
OpenStudy (anonymous):

a = 5, b = 12, c =

OpenStudy (anonymous):

Are you doing the Pythagorean theorem? \(a^2 + b^2 = c^2\) \(5^2 + 12^2 = c^2\) What's 5 * 5?

OpenStudy (anonymous):

25

OpenStudy (anonymous):

Yes, and what's 12 * 12?

OpenStudy (anonymous):

144

OpenStudy (anonymous):

Yes, and what's 25 + 144?

OpenStudy (anonymous):

169

OpenStudy (anonymous):

Yes, now we find the square root of 169. \(\sqrt{169}\) Can you do that?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

Okay, tell me what you get.

OpenStudy (anonymous):

13

OpenStudy (anonymous):

Yep, that's our answer.

OpenStudy (anonymous):

thanx

OpenStudy (anonymous):

\(\bbox [10pt, lime, border:5pt solid black]{\Huge\cal\color{red}\succ\color{blue}{Welcome\ to\ \color{#00A1FF}{Open}\color{#329932}{Study!\color{red}\prec}}}\) You can give medals by clicking 'Best Response'.

OpenStudy (anonymous):

help on finding the equation for a = 4, b = 4, c = pleaz

OpenStudy (anonymous):

Sure, but 1 question per post, so close this and open a new one.

OpenStudy (anonymous):

thanx good to know

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