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OpenStudy (anonymous):
a = 40, c = 41, b = help solve pleaz
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OpenStudy (aaronandyson):
\[A^2 + B^2 = C^2\]
OpenStudy (aaronandyson):
Where 'a' is 40 and 'c' is 41
OpenStudy (aaronandyson):
so to find b
OpenStudy (aaronandyson):
so to find b
OpenStudy (aaronandyson):
\[B^2 = C^2 - A^2\]
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OpenStudy (aaronandyson):
So whats 41*41?
OpenStudy (aaronandyson):
@lokitroll97 ?
OpenStudy (anonymous):
yes
OpenStudy (aaronandyson):
So now solve and tell me what did you get on solving .
OpenStudy (anonymous):
1600+1681=C^2 --- put together and sqrted = 57.28
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OpenStudy (anonymous):
hello
OpenStudy (sleepyjess):
\(40^2+b^2=41^2\) What is \(40^2\)?
OpenStudy (anonymous):
1600
OpenStudy (sleepyjess):
Ok, and \(41^2\)?
OpenStudy (anonymous):
41 is 1681 add and sqrt it and it = 57.28
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OpenStudy (sleepyjess):
No, we aren't adding this time
OpenStudy (anonymous):
oh k -
OpenStudy (sleepyjess):
We get \(1600 + b^2 = 1681\). We need to subtract 1600 from both sides
OpenStudy (anonymous):
so 81 = b^2
OpenStudy (sleepyjess):
yes, and the sqrt81?
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OpenStudy (anonymous):
ninner
OpenStudy (sleepyjess):
I am going to assume that means 9, and if so, then correct
OpenStudy (anonymous):
yes military or air force to be exact
OpenStudy (sleepyjess):
huh?
OpenStudy (anonymous):
its how a pilot communicates the number nine when communicating via telcom
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