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a = 40, c = 41, b = help solve pleaz
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\[A^2 + B^2 = C^2\]
Where 'a' is 40 and 'c' is 41
so to find b
so to find b
\[B^2 = C^2 - A^2\]
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So whats 41*41?
@lokitroll97 ?
yes
So now solve and tell me what did you get on solving .
1600+1681=C^2 --- put together and sqrted = 57.28
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hello
\(40^2+b^2=41^2\) What is \(40^2\)?
1600
Ok, and \(41^2\)?
41 is 1681 add and sqrt it and it = 57.28
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No, we aren't adding this time
oh k -
We get \(1600 + b^2 = 1681\). We need to subtract 1600 from both sides
so 81 = b^2
yes, and the sqrt81?
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ninner
I am going to assume that means 9, and if so, then correct
yes military or air force to be exact
huh?
its how a pilot communicates the number nine when communicating via telcom
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