Question

What is the standard form of the equation of a circle that has its center at (-2, -3) and passes through the point (-2, 0)?
(x + 2)2 + (y + 3)2 = 9
(x − 2)2 + (y − 3)2 = 16
(x − 2)2 + (y − 3)2 = 4
(x + 2)2 + (y + 3)2 = 16
(x − 2)2 + (y + 3)2 = 9

Answer 1

Anyone know? :/ I'm lost

Answer 2

Put the coordinates of these two points into the general equation of a circle and find the radius. Then put the coordinates of the center of this circle and its radius into the equation and you've got the answer.

Answer 3

Ok, so how do i do it?