Question

let (fx)=4x-1, g(x)=x^2+1, h(x)=x+1/3.

Answer 1

find h(g(f(2)))

Answer 2

hi :) what you would do if assemble the functions to make it agree to the given conditions. So first, solve for f(2)

so since f(x)=4x-1, you would substitute the x for 2

you would have: f(2)=4(2)-1

can you solve thus far? @EmeliRivera1 ?

Answer 3

f(2)=7

Answer 4

right. so then the problem would turn into g(7)

how would you set this up? @EmeliRivera1

Answer 5

anyhow, g(7) would be:

g(7)=7^2 +1

so solve that. then the answer for g would be what you substitute for the h function.

Answer 6

If you have any further questions, let me know! :)