Normal saline solution used in IVs is usually around 0.90% m/v or 0.154 M; however, other saline solutions may have a higher or lower concentration of sodium chloride, NaCl, depending on the use. For example, a hypertonic saline solution with a concentration greater than 0.154 M may be used to treat hyponatremia (sodium concentration in the serum is too low).
Calculate the molarity of the NaCl solution when 29.2 g of NaCl is dissolved in 100 mL of water

Question

Normal saline solution used in IVs is usually around 0.90% m/v or 0.154 M; however, other saline solutions may have a higher or lower concentration of sodium chloride, NaCl, depending on the use. For example, a hypertonic saline solution with a concentration greater than 0.154 M may be used to treat hyponatremia (sodium concentration in the serum is too low).
Calculate the molarity of the NaCl solution when 29.2 g of NaCl is dissolved in 100 mL of water

dtan5457 · Answer

The formula for molarity is 
moles solute/liters solute

anonymous · Answer

So if you would work it out what would you get because i dont think im doing it right

dtan5457 · Answer

SO first, you need to find out how many moles there is in 29.2g of NaCl.

The formula for that would be
given mass/formula mass

Na=23g
Cl=35g

Add those together and the formula mass is 58g
The given mass is 29.2 grams, so your moles is about 0.5

As for the liters solute, it must be in liters, 100ml is 10% or 0.1

Molarity for your question is

0.5/0.1

or 5M

M is the units for molarity.

dtan5457 · Answer

Make sense?

anonymous · Answer

Thats what i put but its saying to enter it using dimesions of chemical concentration

dtan5457 · Answer

Can you make a screenshot?

anonymous · Answer

no :(

dtan5457 · Answer

Can you explain what dimensional chemical concentration is? Never heard of it..

anonymous · Answer

I can just go back to that one later because my teacher didnt exaplin it and it doesnt specify in my book

anonymous · Answer

can you help me with this one ? A 2.00 g sugar cube (sucrose: C12H22O11) is dissolved in a 350 mL teapot containing 80∘ C water (density of water at 80∘ C= 0.975 g/mL). What is the molality of the sugar solution?

dtan5457 · Answer

1. Determine the amount of moles in 2g of the sugar cube

given mass/formula mass

c12h22o11=342g

2/342=0.00584795321 mol, but I will round to 0.005848

2. Determine the mass of the solvent. 

density=mass/vol

They give you the density and volume

den=0.975
vol=350

mass=350x0.975=0.341 kg

dtan5457 · Answer

Can you get the molarity from here?

dtan5457 · Answer

you would do 

0.005848/0.341 kg

anonymous · Answer

I would just have to divide it to get the answer?