2 log4 x= (x+2), then
\(\large\color{black}{ \displaystyle 2\log_4 x= x+2 }\) like this?
value x=?
the rules you need (respectively) are: 1. \(\Large\color{black}{ \displaystyle {\rm \color{red}{a}}\log_{\rm \color{blue}{b}} {\rm \color{green}{c}} ~\Rightarrow ~\log_{\rm \color{blue}{b}} ({\rm \color{green}{c}}^{\rm \color{red}{a}}) }\) (exponent in logarithms) 2. \(\Large\color{black}{ \displaystyle \log_{\rm \color{blue}{r}} {\rm \color{red}{s}}= {\rm \color{green}{t}}~~~~\Rightarrow ~~~~{\rm \color{blue}{r}}^{\rm \color{green}{t}}={\rm \color{red}{s}}}\)
first, apply the rule #1 to the left side. What do you then get?
log4 x^2
yes, \(\large\color{slate}{ \log_4(x^2)= x+2 }\)
then apply the second rule
(you can treat \(\large\color{slate}{ x^2 }\) as a single variable when it comes to applying the second rule)
ok
oh, I see the problem you are running into
no simple solution
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