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Mathematics 13 Online
OpenStudy (anonymous):

can someone walk me through this, step by step please

OpenStudy (anonymous):

\[\sum_{n=0}^{\infty} \frac{ 1 }{ (\sqrt11)^n }\]

OpenStudy (anonymous):

Find the sum of the series, if it converges

OpenStudy (phi):

do you know how to find the sum of a geometric series ? https://en.wikipedia.org/wiki/Geometric_series#Formula

OpenStudy (anonymous):

i would really appreciate the help. I am not good with this question at all. and the square root has me thrown off

OpenStudy (anonymous):

I know about \[\frac{ a }{ 1-r }\]

OpenStudy (anonymous):

and how to test for convergence with limit

OpenStudy (anonymous):

and how it is divergent it r is less than -1 or more than 1

OpenStudy (phi):

in this case, r= 1/sqrt(11) = 0.30511...

OpenStudy (phi):

a is 1

OpenStudy (anonymous):

\[\frac{ 1 }{ 1-\frac{ 1 }{ \sqrt11 } }\] ?

OpenStudy (phi):

yes. we can play with that to make it look nicer, but that is the answer.

OpenStudy (anonymous):

do i multiply sqrt 11 to top and bottom so I can subtract the two fractions?

OpenStudy (anonymous):

\[\frac{ 1 }{ \frac{ 11 }{ 11} -\frac{ \sqrt 11 }{ 11 }}\]

OpenStudy (phi):

yes, and that is \[ \frac{1}{\frac{11- \sqrt{11}}{11}} = \frac{11}{11- \sqrt{11}}\]

OpenStudy (phi):

we could also get to \[ \frac{11+\sqrt{11}}{10} \]

OpenStudy (anonymous):

this is where i get really thrown off... how do i simplify this now?

OpenStudy (anonymous):

oh.... the ten... how did you do that?

OpenStudy (phi):

\[ \frac{11}{11- \sqrt{11}} \cdot \frac{11+\sqrt{11}}{11+\sqrt{11}}\]

OpenStudy (anonymous):

this would then be \[\frac{ 1 }{ 10 }(11+\sqrt 11)\]

OpenStudy (phi):

but I would not bother too much. They all mean the same value, about 1.43166...

OpenStudy (anonymous):

hmmm. I thank you kindly sir

OpenStudy (phi):

so to answer the question, you know it converges because | r | < 1 and you can use the formula you posted up above to find the sum

OpenStudy (anonymous):

the problem is, my professor does not want decimals, he wants the fraction form :(

OpenStudy (anonymous):

yes?

OpenStudy (anonymous):

i meant yes, no question

OpenStudy (phi):

people generally would use the last form then... no square roots in the denominator (a hold-over from the days before calculators when dividing by square roots was too hard)

OpenStudy (anonymous):

lol, they are still too hard for me (obviously) :) thanks a bunch

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