Question

Find the derivative of the function: f(x) = 2^sinπ

I have the answer, but I'm not sure how to get to it. I know I have to use the chain rule, but so far all my answers have been wrong.

Can someone walk me through this problem and explain it?

Answer 1

use power rule

Answer 2

2^sinπx

Sorry about that, forgot to add the x!

Answer 3

So, sinπx • 2^sinπx - 1 • (sinπx)' ?

Answer 4

\[y=2^{\sin( \pi x)} \\ \ln(y)=\ln(2^{\sin( \pi x)}) \\ \ln(y)=\sin( \pi x) \ln(2) \\ \text{ differentiate both sides } \text{ keep \in mind } \frac{d}{dx} \ln(g(x))=\frac{g'(x)}{g(x)}\]

Answer 5

Okay, thank you so much!

Answer 6

you don't need any further help?

Answer 7

No, I see what I did wrong and what I need to do from here. Thank you anyway :)

Answer 8

np :)