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Chemistry 16 Online
OpenStudy (dtan5457):

How many moles of hydrogen atoms are there in 1 mole of C6H12O6 molecules?

OpenStudy (dtan5457):

The answer is either 12 or 12(6.0 x 10^23).

OpenStudy (dtan5457):

Can someone explain the difference..

OpenStudy (anonymous):

If the answer is something like 10^23, it's likely asking the amount of atoms/molecules in a solution. If you had 10^23 moles of hydrogen is 10^23 x 1.008 grams

OpenStudy (dtan5457):

Not quit getting it. 12(6.0 x 10^23)=12 moles?

OpenStudy (anonymous):

Are you using Avogadro's number? You have to find the molecular weight of C6H12O6

OpenStudy (dtan5457):

It's just asking for the amount of moles of hydrogen

OpenStudy (dtan5457):

Which is clearly 12, i'm just not sure of the differences

OpenStudy (anonymous):

I haven't taken chemistry for a while, so I don't remember the specifics. By if the weight of C6H1206 is 100, then 100g is 1 mole of C6H1206. You have to find the amount of hydrogen in that, and find the moles of hydrogen

OpenStudy (anonymous):

You use Avogadro's number if you want to know the number of molecules in say a 5 moles of methane

OpenStudy (dtan5457):

Oh you mean, you use that number to find the mass?

OpenStudy (dtan5457):

Based on amount of moles?

OpenStudy (zale101):

1 mole of an atom of a substance equals 6.02 x 10^23 atoms (avogadro's number) . There's 12 moles of hydrogen atoms per 1 mole of C6H12O6 . If the question asked, "How many hydrogen atoms?" then use avogadro's number

OpenStudy (dtan5457):

Quickly refresh me the difference between mole and atom please.

OpenStudy (dtan5457):

I know atom is a single element and a mole can be a large compound. If the question was how many hydrogen atoms however, would 12 not be an answer?

OpenStudy (zale101):

1 mole of hydrogen atoms is 6.022x10^(23) hydrogen atoms. Since we are focusing only about moles, then there's no need to use the avogadro's number so instead we do 1 mole of the element's atoms, or 1 mol of this compound's atoms. Use Av. number only when the question is asking for atoms not mols. Also, every element as atoms, and 1 atoms is very very very tiny, tiny than a mol.

OpenStudy (dtan5457):

Oh, so to get atoms, you would still multiply the avogadro number by moles?

OpenStudy (zale101):

E.g. Let's say me, there's 1 person (mol) of zale, and zale consists of a bunch bunch of atoms (av. number). So, there's 1 mol of zale atoms.

OpenStudy (dtan5457):

Your explanation of how small an atom is, helped me understand the concept, thanks. For some reason my mind thought atom=element

OpenStudy (zale101):

\(3~ mol~Hydrogen\large\frac{6.022*10^{23} ~atoms~ of ~H}{1 mol~of~ H}\) Moles cancel out, and there you solved for atoms. If you are looking for atoms of H, you multiply av. number but if you already been giving the atoms, you don't need to use av. number again since it's already been giving and calculated to you. So instead, you divide the atoms by av. number to get the moles, not atoms. For example: \(3.2*10^{21}~ atoms~Hydrogen\large\frac{1~mol~H}{6.022*10^{23} atoms~H}\) Atoms cancel out and there you solved for moles.

OpenStudy (zale101):

\(\bullet~~\)If you been giving the \(\color{blue}{moles}\) of a certain compound and you are looking for \(\color{red}{atoms}\), then you \(\color{purple}{multiply}\) to get atoms. \(\bullet~~\)If you been giving the \(\color{red}{atoms}\) of a certain compound and you are looking for \(\color{blue}{moles}\), then you \(\color{purple}{divide}\) to get moles

OpenStudy (zale101):

by multiply and dividing, i am referring to the av. numver

OpenStudy (dtan5457):

Good explanation, I'm gonna write this down. Thanks again

OpenStudy (zale101):

No problem

OpenStudy (zale101):

In this case, let me fix my typos "Also, every element has 1 atom, and 1 atom is very very very tiny tiny than a mol."

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