A cotton candy holder is shaped like a cone. The height is 13 in., and the diameter is 8 in.
What is the volume of the holder? Use 3.14 to approximate pi, and round answers to two decimal places if necessary.
_____ in3
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@SolomonZelman
OpenStudy (anonymous):
@satellite73
OpenStudy (anonymous):
1/3 pi x r^2 x h
OpenStudy (anonymous):
am i doing this right 8 times 8 is 64 and 64 times 13 is 832
OpenStudy (anonymous):
and 832 divide by 3 is 277
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@sleepyjess
OpenStudy (anonymous):
@kliedako
OpenStudy (sleepyjess):
Pretty close, we are given the diameter, which is r*2. So to find the radius, we need to do d/2
OpenStudy (anonymous):
8/2?
OpenStudy (anonymous):
@BrownieWuvers @sleepyjess got this
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
okay @kliedako
OpenStudy (sleepyjess):
Yes, so \(\dfrac{4^2*h*\pi}3\)
OpenStudy (sleepyjess):
and the height, h, is given as 13
OpenStudy (anonymous):
69.3?
OpenStudy (sleepyjess):
How did you get to that?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
4 times 4 = 8 and 8 times 13 is 104
OpenStudy (anonymous):
oh. then 34.6
OpenStudy (sleepyjess):
4*4 = 8?
OpenStudy (anonymous):
-.- my bad
OpenStudy (anonymous):
16
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i'm really tired and i was adding lol .-.
OpenStudy (sleepyjess):
haha :)
OpenStudy (sleepyjess):
Ok, so now we have (16*13*3.14)/3
OpenStudy (anonymous):
653 :)
OpenStudy (anonymous):
@sleepyjess
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (sleepyjess):
yes, now 653/3
OpenStudy (anonymous):
217
OpenStudy (sleepyjess):
yep
OpenStudy (anonymous):
Thank you sleepy jes cx
OpenStudy (sleepyjess):
no problem! :)
Still Need Help?
Join the QuestionCove community and study together with friends!