Question

GEOMETRY. RIGHT TRIANGLES. Please see problem in comments

Answer 1

Since the triangles are similar, you can set up this proportion

\[\Large \frac{36}{x+6} = \frac{2x-6}{20}\]

to solve for x

Answer 2

720=2x^2+16x-36
but whats after????

Answer 3

that +16x should be +6x

Answer 4

after you get 720 = 2x^2 + 6x - 36, you would get everything to one side


720 = 2x^2 + 6x - 36

720-720 = 2x^2 + 6x - 36-720

0 = 2x^2 + 6x - 756

2x^2 + 6x - 756 = 0

2(x^2 + 3x - 378) = 0

x^2 + 3x - 378 = 0


now use the quadratic formula to solve for x

Answer 5

ohh