How would I solve this trigonometric limit?
\[\lim_{\theta \rightarrow \Pi/2} \frac{ (1-\sin \theta) }{ (\theta-\Pi/2) }\]
I will use x's if you don't mind \(\large\color{slate}{\displaystyle\lim_{x \rightarrow ~\frac{\pi}{2}}\frac{1-\sin x}{x-\frac{\pi}{2}}}\)
as you plug in pi/2 into top and bottom, you get 0/0 so you can take the derivative on top and bottom (i.e. apply L'Hospital's rule)
when you differentiate the top and bottom you get, \(\large\color{slate}{\displaystyle\lim_{x \rightarrow ~\frac{\pi}{2}}\frac{-\cos x}{1}~~~\Rightarrow~~~~\lim_{x \rightarrow ~\frac{\pi}{2}}~-\cos(x) }\)
then plug pi//2,
Hope this is making sense
Does it make a difference that you replaced the thetas with 'x'?
well, you can imagine that theta's are x's (lol)
it makes no difference. you can re-write it but instead of x's use thetas
theta isn't so special. it is just that I didn't feel like typing ]theta every time
(sorry `\theta` is the actual code )
Okay it makes sense thanks :)
:)
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