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Calculus1 13 Online
OpenStudy (anonymous):

How would I solve this trigonometric limit?

OpenStudy (anonymous):

\[\lim_{\theta \rightarrow \Pi/2} \frac{ (1-\sin \theta) }{ (\theta-\Pi/2) }\]

OpenStudy (solomonzelman):

I will use x's if you don't mind \(\large\color{slate}{\displaystyle\lim_{x \rightarrow ~\frac{\pi}{2}}\frac{1-\sin x}{x-\frac{\pi}{2}}}\)

OpenStudy (solomonzelman):

as you plug in pi/2 into top and bottom, you get 0/0 so you can take the derivative on top and bottom (i.e. apply L'Hospital's rule)

OpenStudy (solomonzelman):

when you differentiate the top and bottom you get, \(\large\color{slate}{\displaystyle\lim_{x \rightarrow ~\frac{\pi}{2}}\frac{-\cos x}{1}~~~\Rightarrow~~~~\lim_{x \rightarrow ~\frac{\pi}{2}}~-\cos(x) }\)

OpenStudy (solomonzelman):

then plug pi//2,

OpenStudy (solomonzelman):

Hope this is making sense

OpenStudy (anonymous):

Does it make a difference that you replaced the thetas with 'x'?

OpenStudy (solomonzelman):

well, you can imagine that theta's are x's (lol)

OpenStudy (solomonzelman):

it makes no difference. you can re-write it but instead of x's use thetas

OpenStudy (solomonzelman):

theta isn't so special. it is just that I didn't feel like typing ]theta every time

OpenStudy (solomonzelman):

(sorry `\theta` is the actual code )

OpenStudy (anonymous):

Okay it makes sense thanks :)

OpenStudy (solomonzelman):

:)

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