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Calculus1 15 Online
OpenStudy (anonymous):

Find the anti-derivative. Help please!!

OpenStudy (anonymous):

\[4xe ^{-x ^{2}}\] how would you find the derivative of that?

OpenStudy (anonymous):

anti derivative ***

OpenStudy (jhannybean):

\[\sf \text{antiderivative} = \int 4xe^{-x^2}dx\]

OpenStudy (jhannybean):

Most likely you'll have to integrate by parts.

ganeshie8 (ganeshie8):

or there is an obvious u-substitution : \(\large u =-x^2\)

OpenStudy (anonymous):

How could U = -x^2 if the du=4x? Am I allowed to multiplay the U by -2?

OpenStudy (jhannybean):

Actually... let's see.

OpenStudy (jhannybean):

What the heck... @ganeshie8 haha

OpenStudy (anonymous):

I'm terrible at taking antiderivatives of e because of the relationship it has with ln and it gets me all confused :(. I don't know how to take the anti derivative of e^(x^2

OpenStudy (jhannybean):

You could pull out the 4 since it's a constant?

OpenStudy (jhannybean):

\[4\int xe^{-x^2}dx\]

OpenStudy (jhannybean):

So now what ganeshie said about making a u sub makes sense !!

OpenStudy (jhannybean):

Letting \(u=-x^2\), \(du = -2xdx \implies -\dfrac{du}{2}=xdx\)

OpenStudy (jhannybean):

So you would have \[4 \cdot \left(-\frac{1}{2}\right) \int e^udu\]

OpenStudy (anonymous):

OHH I see now!! Thank you so much !! @Jhannybean

OpenStudy (jhannybean):

Np :)

OpenStudy (thomas5267):

I don't think \(\int e^{-x^2}dx\) has a closed form solution.

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