Find the anti-derivative. Help please!!
\[4xe ^{-x ^{2}}\] how would you find the derivative of that?
anti derivative ***
\[\sf \text{antiderivative} = \int 4xe^{-x^2}dx\]
Most likely you'll have to integrate by parts.
or there is an obvious u-substitution : \(\large u =-x^2\)
How could U = -x^2 if the du=4x? Am I allowed to multiplay the U by -2?
Actually... let's see.
What the heck... @ganeshie8 haha
I'm terrible at taking antiderivatives of e because of the relationship it has with ln and it gets me all confused :(. I don't know how to take the anti derivative of e^(x^2
You could pull out the 4 since it's a constant?
\[4\int xe^{-x^2}dx\]
So now what ganeshie said about making a u sub makes sense !!
Letting \(u=-x^2\), \(du = -2xdx \implies -\dfrac{du}{2}=xdx\)
So you would have \[4 \cdot \left(-\frac{1}{2}\right) \int e^udu\]
OHH I see now!! Thank you so much !! @Jhannybean
Np :)
I don't think \(\int e^{-x^2}dx\) has a closed form solution.
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