Question

help Will medal and fan. What is restriction rule when (x-5)/(x+1). I know that x cannot be equal to -1 but then there are more restriction

Answer 1

that's the only restriction I think...

Answer 2

\[\frac{ (x-5) }{ (x+1) }\] no there are more

Answer 3

x is all real numbers

Answer 4

Well what value of x would cause this function to be undefined...

Answer 5

these are the answers

Answer 6

oh... I see this is only part of the question...

Answer 7

whacha mean?

Answer 8

can you just tell me the answer and explain why?

Answer 9

Well when I saw the question you posted... you never mentioned this came from another equation. I assumed it was a "closed question" meaning that there were no other variable that may affect the result

Answer 10

so what do you think the answer gonna be either A or B? I don't remember the other restriction I know that x cannot be -1 but then they had -9 and -5 so which one is it??

Answer 11

x != -1, x != -9

Answer 12

but it was cancelled out

Answer 13

since theres no other choice I'll pick a

Answer 14

Just because the (x+9) was cancelled out doesn't mean it does not exist anymore. If you graph this equation you'll find that there is a hole at x= -9 and a asymptote at x=-1

Answer 15

ok cause I had the other problem that doesn't included the other restriction and I chose that

Answer 16

but now im gonna change that too

Answer 17

The restriction is also -9. You must remember to check restrictions on the original equation.

Originally, the denominator was x^2+10x+9

Plug -9 into that and you still get 0.