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OpenStudy (anonymous):
Given f(x)=x^2+1,fg(x)=x^2+4x+5
Find the function of g.
@mathmath333
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OpenStudy (anonymous):
\[x^2(g(x))+1=x^2+4x+5\]
OpenStudy (anonymous):
separate your 5 \[fog(x)=(x^2+4x+4)+1\]
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
\[fog(x)=f(g(x))\]It's a way of representing composite functions
All I did was separate your 5 into 4 and 1
\[fog(x)=f(g(x)=x^2+4x+4+1\]
OpenStudy (anonymous):
okay
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OpenStudy (anonymous):
Now we must substitute f(x)=x^2+1 ?
OpenStudy (anonymous):
that is not needed really just notice your first 3 terms, they form an identity
OpenStudy (michele_laino):
pleasenote that we can write:
\[f\left( {g\left( x \right)} \right) = {\left( {g\left( x \right)} \right)^2} + 1\]
OpenStudy (michele_laino):
furthermore, we have:
\[{x^2} + 4x + 5 = {x^2} + 4x + 4 + 1 = {\left( {x + 2} \right)^2} + 1\]
OpenStudy (michele_laino):
nemely:
\[f\left( {g\left( x \right)} \right) = {x^2} + 4x + 5 = {x^2} + 4x + 4 + 1 = {\left( {x + 2} \right)^2} + 1\]
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OpenStudy (anonymous):
so the function of g is
g(x)=x+2?
OpenStudy (michele_laino):
that's right!
OpenStudy (anonymous):
Thnx @Michele_Laino and Nishant_Garg
OpenStudy (michele_laino):
thanks! @MARC_
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