help and will medal.. Why can't I get to any of the answer?
@iGreen
Do we flip the 2nd fraction and cross multiply? xD
When dividing flip the second fraction and multiply, this requires factoring, it will look nice eventually, so what have you tried?
It's more so to test if you can factor
\[\frac{ (x-3)(x-4) }{ (X-5)(x-4) } \div \frac{ 3(x-5)(x-3) }{ 12(x+1)(x-5) }\]
is it correct? Any mistake?
Mhm not quite, I see some of your factors are wrong \[x^2+x-12 \implies (x+4)(x-3)\] \[(x^2-x-12) \implies (x+4)(x-5)\]
\[3x^2-24x+45 \implies 3(x-3)(x-5)\] so I see you got this one right
Your last one looks good to
So your first two factoring were wrong
\[\frac{ (x+4)(x-3) }{ (x+4)(x-5) } \times \frac{ 12(x+1)(x-5) }{ 3(x-5)(x-3) }\] cancel away
ok so i got 4(x+1) / x-5 when i cross it out
Yeah, that sounds good to me!
THnaks Batman you're my hero
Np :)
Join our real-time social learning platform and learn together with your friends!