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Mathematics 10 Online
OpenStudy (anonymous):

help and will medal.. Why can't I get to any of the answer?

OpenStudy (anonymous):

OpenStudy (r_josh10):

@iGreen

OpenStudy (igreen):

Do we flip the 2nd fraction and cross multiply? xD

OpenStudy (anonymous):

When dividing flip the second fraction and multiply, this requires factoring, it will look nice eventually, so what have you tried?

OpenStudy (anonymous):

It's more so to test if you can factor

OpenStudy (anonymous):

\[\frac{ (x-3)(x-4) }{ (X-5)(x-4) } \div \frac{ 3(x-5)(x-3) }{ 12(x+1)(x-5) }\]

OpenStudy (anonymous):

is it correct? Any mistake?

OpenStudy (anonymous):

Mhm not quite, I see some of your factors are wrong \[x^2+x-12 \implies (x+4)(x-3)\] \[(x^2-x-12) \implies (x+4)(x-5)\]

OpenStudy (anonymous):

\[3x^2-24x+45 \implies 3(x-3)(x-5)\] so I see you got this one right

OpenStudy (anonymous):

Your last one looks good to

OpenStudy (anonymous):

So your first two factoring were wrong

OpenStudy (anonymous):

\[\frac{ (x+4)(x-3) }{ (x+4)(x-5) } \times \frac{ 12(x+1)(x-5) }{ 3(x-5)(x-3) }\] cancel away

OpenStudy (anonymous):

ok so i got 4(x+1) / x-5 when i cross it out

OpenStudy (anonymous):

Yeah, that sounds good to me!

OpenStudy (anonymous):

THnaks Batman you're my hero

OpenStudy (anonymous):

Np :)

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