Question

Solve the equation in the real number system

Answer 1

@akitav

Answer 2

x=-2 , -1,2

Answer 3

x=-1,2

Answer 4

x=-3,-1,2

Answer 5

x=-3/2 , -1,2

Answer 6

obiv u gootaaaaaa go like now because like dang......

Answer 7

not gone, still here. takes a bit to solve

Answer 8

no i meant her she just needs to go...... @Obviamber

Answer 9

lets compare answers ok

Answer 10

I am thinking

Answer 11

I got D!

Answer 12

What are the answer choices

Answer 13

look ^

Answer 14

find a number for which the equation becomes zero I plugged x= 1 and 2 and it worked for 2 ( this method is hit and trial so the easiest) this means that x-2 is a factor of the given polynomial. so use long division and divide the polynomial ( the left part of the equation) by (x-2) you'd get\[2x^2+5x+6\] as the quotient and on solving this quadratic equation you get the other two roots. the final answer is
x = 2,-1,-3/2

Answer 15

your answer is correct :)

Answer 16

we got the same answer

Answer 17

Yeah that's right, I got that but I'm confused so I wasn't sure

Answer 18

next?