Question

1/ ^3 sqrt x^x-6

Answer 1

Can you type that with the equation editor?

Answer 2

\[1/^3\sqrt{x^-6}\]

Answer 3

@jwhite12

Answer 4

\[\frac{ 1 }{ \sqrt[3]{x-6} }\]
?
What are you supposed to do with that? What's the question?

Answer 5

Simplify the given expression to rational exponent form and justify each step by identifying the properties of rational exponents used. All work must be shown.
@jwhite12

Answer 6

Taking the third root of something is the same as raising it to the 1/3 power.

Answer 7

I'm sorry but I don't get what you said. What do you mean by the third root of something?

Answer 8

@jwhite12

Answer 9

\[\sqrt[3]{ }\] is the third root

Answer 10

So your problem is taking the third root of (x-6), in the denominator

Answer 11

To solve it what I did was \[1/x^-6/3\] then \[1/x^-2\] Im confused about the 1 in the numerator. @jwhite12

Answer 12

I'm confused about what step you did there. Did you try to divide by 3?

Answer 13

I divided the -6 by 3 @jwhite12

Answer 14

You can't do that. They just want you to rewrite the radical expression as an exponential expression. So \[\sqrt[3]{x-6}=(x-6)^{\frac{ 1 }{ 3 }}\]

Answer 15

The -6 is an exponent of x. @jwhite12

Answer 16

Ohhhhh ok. Sorry, I couldn't tell what your exponents were.
\[\sqrt[3]{x^{-6}}\]

Answer 17

Ok, I'm with you. Yes, you were right then. But I think can do one more step.

Answer 18

\[\frac{ 1 }{x ^{\frac{ -6 }{ 3 }} }=\frac{ 1 }{x ^{-2} }\]
That's what you had, right?