Question

How many liters of methane gas (CH4) need to be combusted to produce 12.4 liters of water vapor, if all measurements are taken at the same temperature and pressure? Show all of the work used to solve this problem.

CH4 (g) + 2 O2 (g) yields CO2 (g) + 2 H2O (g)

Answer 1

I did this : 12.4 g H2O x (1 mol CH4 divided by 2 mol H2O = 6.20 L CH4

Answer 2

I just wanna know If i did it right

Answer 3

@jordanloveangel @jeffyblood @kathlyn98 @KatieMTB @Luigi0210 @Librarian @LiteNing1337 @LittleRedRiding @NathalyN @omgitsjc @Ondinana @OpenStudyRocks5* @pooja195 @raynagarcia @sammixboo @Squirrels @shaleiah @SimonN1995

Answer 4

Pleaz?

Answer 5

@TheSmartOne @taylor12344 @Thatkid_marc @thelaw2 @vera_ewing @xo.minnie.xox @xstreetprowl @YOUNGSUPERMAN @zzr0ck3r

Answer 6

im not good at chemi

Answer 7

I got the same answer, but at the beginning H20 is in liters, not grams, so you have to use stoichiometry.

Answer 8

ok

Answer 9

I can show the work I did if you want

Answer 10

yes pleaz

Answer 11

stiociometry is really hard for me, Sorry

Answer 12

*stoichiometry

Answer 13

Oh I got the second problem done its:
You know moles = volume/molar volume (Vm)
n(H2O) = 12.4/(Vm)
n(CH4)=n(H2O) * 0.5 = 6.2/Vm
V(CH4) = 6.4/Vm *Vm = 6.2L

Answer 14

Do you still need help. Is this a certain curriculum...?

Answer 15

why did u X it by 0.5?

Answer 16

and it's Chemistry

Answer 17

@thelaw2

Answer 18

Sorry aye, I'm not very great in chemistry. All language arts and history is my thing. :P

Answer 19

@cecormier I think that @thelaw2 is using a different formula that they have memorized, from physics perhaps? But if you are supposed to be using stoichiometry, I'm pretty sure that my work is correct.

Answer 20

Thank you :)