Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:
3N2H4(l)→4NH3(g)+N2(g)

A.) 2.0 mol N2H4

thank you :)

Question

Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:
3N2H4(l)→4NH3(g)+N2(g)

A.) 2.0 mol N2H4

thank you :)

dtan5457 · Answer

Are you saying how many moles of NH3 will form if 2 moles of N2H4 are used, or how many moles are used in the original equation?

dtan5457 · Answer

If it's from 2 moles of N2H4.

You need to find what number 3 divided by turns into 2. (1.5)

The ratio factor is 1.5

So just divide 4NH3 by 1.5

4/1.5 will be your amount of moles of NH3 if 2 moles of N2H4 are used.