Question

Lance has a moment of inertia of 420 kg m2 while riding the Rotor. The floor of the Rotor drops out from under its riders once it reaches the angular velocity (ω omega) of 1.6 radians per second. Calculate his angular momentum.

Remember to identify all data (givens and unknowns), list equations used, show all your work, include units, and the proper number of significant digits to receive full credit.
@Abhisar @ganeshie8 @Nnesha @zepdrix @TheSmartOne @pooja195

Answer 1

PLEAAAAAAAAAASEEEEE HEEEELPP!!

Answer 2

1.6*pi radians / second is the angular speed of the rotor.

Answer 3

Do you know that much?

Answer 4

no i really need help with it

Answer 5

Given the moment of inertia or 420 kg m^2, multiply it by the angular speed to get Lance's angular momentum.

Answer 6

Try it out :)

Answer 7

is that all i need to do?

Answer 8

I think so i dont see anything else that you would need to do unless im doing this wrong =/

Answer 9

@shamim ?

Answer 10

wat do u think @shamim ?

Answer 11

I would think thats all you need to do

Answer 12

ok

Answer 13

Ok. Do u know p=mv

Answer 14

no

Answer 15

p=linesr momentum

Answer 16

m=mass of that body

Answer 17

ikd any of this.. but anything that'll get this problem slved will help

Answer 18

v=velocity of that object

Answer 19

so wat do i need to do i dont have all the time.

Answer 20

is this a test?

Answer 21

no! why do u always ask me that question! its my physics hw if it was a test I would've never posted it on here.

Answer 22

Was just curious anyways continue on you said im running out of time

Answer 23

@TheSmartOne HELP MEEEE ANYONE PLZZZ!!!!

Answer 24

P=mv..... for linear motion
L=I*omega.....for angular motion

Answer 25

ok?

Answer 26

Now for ur math problem u need to use the formuls
L=I*omega

Answer 27

Here L=angular momentum

Answer 28

I=moment of inertia

Answer 29

so basically wat pooja suggested?..

Answer 30

Omega=angular velocity

Answer 31

so basically wat pooja suggested?..

Answer 32

Given I=420kg.m^2
Omega=1.6rad/sec

Answer 33

L=?

Answer 34

\[\sf Angular~Momentum = Moment ~ of ~ inertia \times Angular~Velocity\]

And in symbols that would be
\[\sf L = I \times \omega \]

Answer 35

They have given us that
\(\sf Moment~ of~inertia= 420~kg m^2\)

Answer 36

right

Answer 37

And that
\(\sf Angular~velocity = 1.6~radians~per~ second\)

Answer 38

correct :)

Answer 39

And since it is in radians we don't need to change it to degrees because it has to be in radians :)

Answer 40

okay!

Answer 41

Now we just plug it in :)

Answer 42

\(\Large\sf Angular~momentum= 420 ~kg~m^2\times 1.6 \frac{rad}{sec}\)

Answer 43

Oh wooow! okaayyy!

Answer 44

is it okay if you can help me answer this or explain this in complete sentences plz?

Answer 45

:)

Answer 46

So basically, you put the formula we used at the top. And then write what we were given. And then show how we plugged it in. And how we solved for it and got the correct units. And then round to the correct number of significant figures.

Answer 47

And ta-da you receive full credits :)

Answer 48

Okay I will work on that and have you check if it looks right for me plz :)

Answer 49

Sure :)

Answer 50

I honestly thought this problem was hard, until I remembered the formula xD

All those sentences confused me. I had to remove all that useless info and just take the numbers they gave me. Haha

Answer 51

hahaha that is true the sentences really got me at first, but then with the formula and when you showed me how to do it, it was a piece of cake!

Answer 52

i have a question @pooja195

Answer 53

I can clearly see that you are a barbie girl.

Oh baby baby..

Answer 54

Awk moment when this is from the physics test

Answer 55

o.o