Solve triangle UVW if m angle U = 41°, w = 12, and v = 13. A) m angle U = 41°, m angle V ≈ 75.7°, m angle W≈ 63.3°, and u ≈ 8.8, v = 13, and w = 12 B) m angle U = 41°, m angle V ≈ 63.3°, m angle W ≈ 75.7°, and u ≈ 9.9, v = 13, and w = 12 C) m angle U = 41°, m angle V ≈ 63.3°, m angle W ≈ 75.7°, and u ≈ 8.8, v = 13, and w = 12 D) m angle U = 75.7°, m angle V ≈ 41°, m angle W ≈ 63.3°, and u ≈ 8.8, v = 12, and w = 13
@Jamierox4ev3r
wow this involves a lot of work lol hold on :P
sorry lol i just dont understand it
its basically the same process as the other problems we've done. It just involves solving for more things T_T
yea.. :/
I'm just going to change uvw to abc if you don't mind...makes things easier for me
yea thats fine
alright wow this problem though...tedious as heck! btw, we can eliminate option D right off the bat, it contradicts the first part of the problem lol
\[u=\sqrt{w^2+v^2-2wvcos(U)}\]
you can solve for side a (or u) first
12^2 +13^2 - 2(12)(13)cos(U)
yep! and once you solve the side, you can possibly switch to law of sines if you so choose to find the rest!
I actually have to go really soon, its really late for me ;-;
ok just 1 more min plz
144 + 169 - 312 = 6
and...she leaves me :/
i got no answer :c
@TheSmartOne
@Michele_Laino
@Jhannybean
I haven't learned this yet :/ Maybe @Jhannybean @Michele_Laino @perl @Miracrown can help you :)
Please I apply the Carnot Theorem, so I get: \[{u^2} = {v^2} + {w^2} - 2vw\cos 41 = 169 + 144 - 312\cos 41\] what is u?
angle U = 41 degrees
yes! |dw:1424424295852:dw|
ok so whats next
next please you have to perform the computation, namely: \[{u^2} = 169 + 144 - 312\cos 41 = 313 - 312 \cdot 0.755 = 313 - 235.6 = 77.4\]
so we have: \[{u^2} = 77.4\]
ok but in the choices its 75.7
please you have to look at the values for u
so you have to compute this: \[u = \sqrt {77.4} = ...?\]
ohh so it would be 8.7
I think 8.8 since you have to round off your result
yea true
ok so now we should find v
please note that in order to find V, you can apply the sines Theorem
namely: \[\frac{v}{{\sin V}} = \frac{u}{{\sin 41}}\]
and substituting the values for u and v, we get: \[\frac{{13}}{{\sin V}} = \frac{{8.8}}{{\sin 41}}\]
next you have to solve that equation for sinV, so I can re-write it as follows: \[\sin V = \frac{{13}}{{8.8}}\sin 41\]
please, what is sinV?
would it be 1.32
no, I don't think since sinV has to be a number less than 1
hint: \[inV = \frac{{13}}{{8.8}}\sin 41 = \frac{{13}}{{8.8}} \cdot 0.656 = ...?\]
oops... \[\sin V = \frac{{13}}{{8.8}}\sin 41 = \frac{{13}}{{8.8}} \cdot 0.656 = ...?\]
0.96
ok!
so what is V?
please you have to use your scientific calculator
i dont know how to get v
please you have to use the inverse function option, nevertheless here i your value for V: V=73.74 degrees, namely: V = 74 degrees
oops... here is your value...
oh ok so i think the answer would be A
yes! That's right!
ok thanks for your help :)
thank you! :)
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