How many moles of lithium metal would need to react with excess oxygen gas to produce 4 moles of lithium oxide in the following reaction? 2 Li + O2 → Li2O
@Demonx341
yes?
I need to know how to find the limiting reactant. I know that the limiting reactant is what ends the chemical reaction, & the excess is what's left after the reaction. I just don't know how to determine that by looking at an equation. Can you help?
@linn99123
this isn't a limiting reactant question. In a limiting reactant problem, you would be given \(known amounts\) of both starting materials and asked to predict a yield. Here, you're given an amount of product that \(needs\) to be formed, and you need to find the amount of \(one\) reactant necessary to make it. Look at the mole ratios from the balanced equation. That tells you everything
So I just find the molar mass?
no, you need to look at the coefficients in front of the formulas
If you're going to produce 4 moles of lithium oxide, how many \(moles\) of lithium metal are needed? that's exactly what this question is asking
Right. How do I find that out though? Wouldn't there have to be more moles of lithium metal if it is going to react with excess oxygen gas?
they're telling you "excess" oxygen gas to make sure that all the lithium metal is used up. the amount of oxygen that's actually used isn't needed here
in order to make 4 moles of lithium oxide, how many moles of lithium are used?
the balanced reaction tells you that every time you USE 2 moles of lithium, you MAKE 1 mole of lithium oxide.
Oh. I just didn't understand how to read the equation to find the information. I guess it's actually really simple.Thank you.
so what do you think the answer is?
8
it is, GJ
Yep
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