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OpenStudy (anonymous):
OpenStudy (anonymous):
?
OpenStudy (anonymous):
do you know the Pythagorean theorem
OpenStudy (anonymous):
nvr mind u cant do that here hold on
OpenStudy (anonymous):
im sorry I dont know this what grade r u in
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OpenStudy (anonymous):
11th and answer???
OpenStudy (anonymous):
@bibby @pooja195
OpenStudy (anonymous):
@iGreen
OpenStudy (anonymous):
@ribhu
OpenStudy (igreen):
\(AC^2 + BC^2 = AB^2\)
Plug in what we know:
\(5^2 + 12^2 = AB^2\)
Solve for 'AB', tell me what you get.
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OpenStudy (anonymous):
13?
OpenStudy (igreen):
Yep, you got it.
OpenStudy (igreen):
Now we can set up a proportion.
\(\dfrac{AC}{AB} = \dfrac{AB}{AD}\)
Plu gin what we know:
\(\dfrac{5}{13} = \dfrac{13}{AD}\)
Cross multiply and solve for 'AD'.
OpenStudy (igreen):
Can you do that? @callmechris99
OpenStudy (anonymous):
hmmm let me try real quick
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OpenStudy (anonymous):
is 65 the answer
OpenStudy (igreen):
No..
Cross multiplying gives us:
5 * AD = 13 * 13
5AD = 169
Divide 5 to both sides, what's 169 / 5?
OpenStudy (anonymous):
i did that
OpenStudy (igreen):
Yes, but 65 is still incorrect. Tell me what you get when you divide 169 / 5.
OpenStudy (anonymous):
which is 33.8
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OpenStudy (anonymous):
hahah
OpenStudy (igreen):
Yep, you got it.
OpenStudy (igreen):
\(AD = AC + CD\)
Plug in what we know:
\(33.8 = 5 + CD\)
Subtract 5 to both sides what's 33.8 - 5?
OpenStudy (anonymous):
6.75
OpenStudy (igreen):
Um, no check again.
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