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Mathematics 11 Online
OpenStudy (anonymous):

question below thanks fans and medals as always

OpenStudy (anonymous):

OpenStudy (anonymous):

?

OpenStudy (anonymous):

do you know the Pythagorean theorem

OpenStudy (anonymous):

nvr mind u cant do that here hold on

OpenStudy (anonymous):

im sorry I dont know this what grade r u in

OpenStudy (anonymous):

11th and answer???

OpenStudy (anonymous):

@bibby @pooja195

OpenStudy (anonymous):

@iGreen

OpenStudy (anonymous):

@ribhu

OpenStudy (igreen):

\(AC^2 + BC^2 = AB^2\) Plug in what we know: \(5^2 + 12^2 = AB^2\) Solve for 'AB', tell me what you get.

OpenStudy (anonymous):

13?

OpenStudy (igreen):

Yep, you got it.

OpenStudy (igreen):

Now we can set up a proportion. \(\dfrac{AC}{AB} = \dfrac{AB}{AD}\) Plu gin what we know: \(\dfrac{5}{13} = \dfrac{13}{AD}\) Cross multiply and solve for 'AD'.

OpenStudy (igreen):

Can you do that? @callmechris99

OpenStudy (anonymous):

hmmm let me try real quick

OpenStudy (anonymous):

is 65 the answer

OpenStudy (igreen):

No.. Cross multiplying gives us: 5 * AD = 13 * 13 5AD = 169 Divide 5 to both sides, what's 169 / 5?

OpenStudy (anonymous):

i did that

OpenStudy (igreen):

Yes, but 65 is still incorrect. Tell me what you get when you divide 169 / 5.

OpenStudy (anonymous):

which is 33.8

OpenStudy (anonymous):

hahah

OpenStudy (igreen):

Yep, you got it.

OpenStudy (igreen):

\(AD = AC + CD\) Plug in what we know: \(33.8 = 5 + CD\) Subtract 5 to both sides what's 33.8 - 5?

OpenStudy (anonymous):

6.75

OpenStudy (igreen):

Um, no check again.

OpenStudy (anonymous):

28.5

OpenStudy (anonymous):

28.8***

OpenStudy (igreen):

Yep, that's our answer.

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