OpenStudy (austinl):

Haven't been on here in a while, let alone asked a question; however, here I am asking for help. This problem is an engineering statics problem and I will attach a screen capture in a reply below for ease of viewing and clarity.

2 years ago
OpenStudy (austinl):
2 years ago

Parth (parthkohli):

Some stupid bug with OS. Not an engineering student, but I can tell that we're gonna be working with torque here.

2 years ago
OpenStudy (austinl):

Torque and moments are what they'll be. I have fallen behind in this class, and failed it last semester through no fault of my own... so be patient if I'm a little slow to catch on haha

2 years ago
Parth (parthkohli):

OK, but please don't trust me with this question... I'll try my best.\[\vec\tau = \vec r \times \vec F\]For one, we know that the force and position are perpendicular in both the cases, so there's that. And we can write \(\tau = rF\sin 90 = rF\).

2 years ago
Parth (parthkohli):

It's given that the torque acts clockwise... what does that tell us about the force?

2 years ago
OpenStudy (austinl):

Does that mean the force is negative in regards to the established axes?

2 years ago
Parth (parthkohli):

Eh, I don't know either. :P I'll just attempt a solution which I'm pretty sure will be wrong, but well, no harm in trying... \(120 ~Nm = 0.205/2 ~m \times F_1~N \Rightarrow F_1 = 1171 N\) \(85 ~Nm = 0.160/2 ~m \times F_2 ~ N \Rightarrow F_2 = 1062.5 N\)

2 years ago
Parth (parthkohli):

Now I'm not sure what we're supposed to do with these forces, but my intuition says that we should consider the case when these forces act downward (the force is radial, so it'd act upward and downward at different times). When they act downward, they contribute to the weight of the block too.

2 years ago
Parth (parthkohli):

Another factor here is that this block.... uh... gear reducer or whatever it is called is asymmetrical. Anything we can do about that?

2 years ago
Parth (parthkohli):

hmm, so what do you think?

2 years ago
OpenStudy (austinl):

I'm honestly so lost right now it isn't even funny. I don't want to waste your time.

2 years ago
Parth (parthkohli):

Hell no, I like this problem. You need someone experienced... @Michele_Laino @Kainui to the rescue!

2 years ago
OpenStudy (michele_laino):

I think that we have to apply two equations. The first equation is: \[{F_A} + {F_B} = R\] where \[{F_A},\quad {F_B}\] are the magnitude of the vectors: \[{{\mathbf{F}}_{\mathbf{A}}},\quad {{\mathbf{F}}_{\mathbf{B}}}\] |dw:1424459533519:dw|

2 years ago
OpenStudy (michele_laino):

|dw:1424459676742:dw|

2 years ago