Question

Please help me, this problem is driving me crazy.

Simplify 4 over the quantity of negative 2 minus 2i.

Answer 1

\[4 \over -2-2i\]

Answer 2

@rainstorm12

Answer 3

multiply top and bottom of the fraction by the complement of -2 - 2i which is -2 + 2i
this removes the imaginary part of the complex number from the denominator

Answer 4

ok, what is 2i multiplied by 2i btw?

Answer 5

i^2 = -1

Answer 6

4- 2i^2 = -8 + 8i

Answer 7

is that right so far?

Answer 8

thats correct for the numerator

Answer 9

(-2 - 21)(-2 + 2i) = ?

Answer 10

that should be an i not a 1

Answer 11

idk what 2i multplied by 2i is

Answer 12

its -2i * 2i

-2 * 2 = -4
and i^2 = -1

Answer 13

so it equals -1 *-4

Answer 14

by definition i = sqrt(-1) so i^2 = -1

Answer 15

i keep coming to a solution of i = 1