Question

Help with damped functions please

Answer 1

A weight is suspended from the ceiling by a steel spring. The weight is pulled downward from its equilibrium position and released. The resulting motion of the weight's distance in inches from equilibrium is described by the function \[A(t)=2e^-tcos(3t)\], in which t is the time in seconds. Calculate the weight's distance from equilibrium in inches after 0.5 seconds(round to the nearest hundredth).

Answer 2

A(t)=2e^-t lel it messed up. but E has an exponent of -t

Answer 3

@freckles could you assist please

Answer 4

I believe I would just fill in .5 for t

Answer 5

sounds fine to replace t with .5
the function is describe as A being weight's distance in inches from the equilibrium
where t is the time is seconds

Answer 6

2(0.6065306)(0.0707372)

Answer 7

so many decimals

Answer 8

http://www.wolframalpha.com/input/?i=2*exp%28-1%2F2%29*sin%283%2F2%29
using handy dandy calculator for the rest
that product should be 1.21

Answer 9

i got .9 in the end s:

Answer 10

i mean .09

Answer 11

i put sin and instead of cos

Answer 12

you are correct :)
.09

Answer 13

It was right then :D

Answer 14

question though how can you tell if it is above or below the equillibrium

Answer 15

I assume that has to deal with is the answer positive or negative

Answer 16

Alrights so this would be above the equilibrium then

Answer 17

I do believe so :)

Answer 18

and it is 0 inches away when A=0
So it would make since if you get A=negative that is would be below

Answer 19

thank you :D

Answer 20

sense*