Miranda bought some apples and oranges at the store for fruit salad. Owen bought three times as many apples and twice as many oranges. Miranda has 5 fruits in her bag, but Owen has 12 fruits in his bag. How many apples did Miranda purchase?
is owens equation 3a + 2o=12?
Lets use a for apples and o for oranges. 12=3a+2o M=5 O=12 So yes, you're right.
and then marandas equation would be a+0=5
Yes.
but how do i solve it then
"Miranda bought some apples and oranges at the store for fruit salad. Owen bought three times as many apples and twice as many oranges."
well its a multiple choice question its ether 1 2 3 5
@TheSmartOne I'm kinda stuck on this.
thanks for trying though
No problem.
Hmmm.
Well first we would need to label what Miranda's fruits are.
i think i got it but tell me if i wrong or not
i think the 'a' term is 17 because i have to single out one of the terms
So if Miranda has oranges and apples. And o + a = 5 because she has 5 fruits so Miranda's equation would be o + a = 5
and 'o' equals 10
yes
And Owen has 3 times as many oranges and 2 times as many apples And for Owen, the equation would be 3a + 2o = 12
yea
So your equation was correct :) And now we use those 2 equations and solve for a :)
but im trying that and im not getting the right answer
3a + 2o = 12 a + o = 5 So those are our two equations. We can solve them in many ways. There are actually 3 ways to solve them-- Elimination, Substitution, and graphing Which method do you know or do you find the esaist? :)
substitition
So since we are solving for a, lets make this equation a + o = 5 If we move around terms in that so that we get what o = ? we can substitute that back in and solve for a :)
So a + o =5 o = ?
@inowalst You definitely tagged the correct person ;)
xD Haha, of course I did!
i am very confused
So \(\sf a + o =5\) Lets subtract a from both sides :) \(\sf a + o - a = 5- a\) What do we get if we simplify that?
o = -5a?
Actually, no. \(\sf a - a + o = 5 - a\) Which can be simplified to \(\sf o = 5 - a\)
oh ok
And now we plug that in to our first equation we had which is \(\sf 3a + 2o = 12\)
So since \(\sf o = 5- a\) we plug that into \(\sf 3a +2o =12\) And now just solve for a :) \(\sf 3a +2o =12\) \(\sf 3a +2\color{red}{(5-a)} =12\)
ohh ok thank you so much! im not completely sure how to give you a medal but yes
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ok cool thank you
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