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Mathematics 15 Online
OpenStudy (anonymous):

Find the exact value of the following function. Show your work and explain the steps you take to find the value. sec(17pi/6) THANK YOU!! (:

OpenStudy (anonymous):

I still don't get it ):

OpenStudy (anonymous):

@Directrix

OpenStudy (anonymous):

Find the exact value of each of the following. In each case, show your work and explain the steps you take to find the value. 1. sin 17pi/6 2. tan 13pi/4 3. sec 11pi/3 I am not sure how to approach this. I looked at the unit circle and know that all three of these go around the circle almost once or one time. Do I have to look at the reference angles for this? Also how does sin, tan and sec affect the answer? I know tan (theta)=y/x, sec(theta)= 1/x and sin(theta)= y.

OpenStudy (anonymous):

find \(\frac{17\pi}{6}\) on the unit circle, which is coterminal wtih \(\frac{5\pi}{6}\) because \[\frac{17\pi}{6}-2\pi =\frac{6\pi}{6}\]

OpenStudy (anonymous):

look at the first coordinate on the unit circle, that is cosine

OpenStudy (anonymous):

take the reciprocal of that number, that is secant

OpenStudy (anonymous):

the first coordinate is pi/6 right?

OpenStudy (anonymous):

so 6/pi is secant

OpenStudy (anonymous):

no you got a cheat sheet?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

find \(\frac{5\pi}{6}\) and look at the ordered pair let me know when you find it

OpenStudy (anonymous):

(-rad3/2,1/2)

OpenStudy (anonymous):

quadrant 2

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

the first coordinate is cosine

OpenStudy (anonymous):

secant is x?

OpenStudy (anonymous):

so -2/rad3

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

that's the final answer?

OpenStudy (anonymous):

YES

OpenStudy (anonymous):

THANK YOU!!!!!!!!!!!!!!!!!!!!!

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

unless you have to rationalize the denominator

OpenStudy (anonymous):

I don't have to, my teachers prefers it as is.

OpenStudy (anonymous):

teacher*

OpenStudy (anonymous):

in which case you have to write \[-\frac{2\sqrt3}{3}\]

OpenStudy (anonymous):

k good, your teacher has common sense

OpenStudy (anonymous):

lol

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