**PLEASE HELP** Consider the right triangle ABC given below; use trig ratios to answer this question. a. What is the length of the shorter leg of the triangle ABC? b. What is the length of the hypotenuse of triangle ABC? The entire triangle is triangle ABC
This is the triangle
AB*sin(30) = 15 <- solve for AB to get that distance. CB*sin(60)=15 <- solve for CB. You can then either use pytagoreas theorom t solve for AC or set up cos trig like: ABcos(30)+BCcos(60) = AC
for ab I got 14.5 and cb 14.13
should I do (14.13)ˆ2+bˆ2=(14.5)ˆ2
I meant to square each term
you did something wrong... perhaps you tried a calculator and used radians instead of degrees? sin(30) = .5 so ABsin(30) = 15 -> .5AB = 15 -> 2(15) = AB -> AB = 30
is sin 60 .87?
.87(cb)=15
then I divide 15 by .87?
yep
17.24?
so the hypotenuse is 47.24?
what no lol. technically ABC does not have a hypotenuse because it is not a right triangle. AB would be the hypotenuse of one of the two triangles and AC the hypotnuse of the other. A triangle has to be a right triangle to have a hypotenuse. Technically only the first question has an answer as that length is AC. the second question is invalid because ABC is not a right triangle.
I meant shorter leg
oh no the shorter leg of triangle ABC is AC which is -> AC = 15/sin(60) = 17.32 '
ft
what did you do to get 47?
I added ABcos(30)+BCcos(60) = AC
So, there's no answer for the second question?
whoops sorry I labelled that wrong. You are correct for AC the shorter leg is BC which is 17.32 feet. I apologize for that one; my bust.
So it is 47 ft?
no you can give BC and AB as the two hypotenuses for their respective right triangles (you need to put point D at where the right angle is created on line AC. but for triangle ABC there is no hypotenuse because it is not a right triangle.
AC is 47 feet the shorter leg is BC which is 17.32 ft.
Thanks
1st question: 17.32 ft 2nd question: ABC has no hypotenuse because it is not a right triangle.
sure
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