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Find the general solution of each differential function: dy/dx = 2xe^y
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same question runger
no it isn't. Same instructions but I need help finding antiderivative of 1/e^y
-e^-y
how did you get that?
take (-e^-y)'= e^(-y)
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or just let -y =u and do something on e^u
e^-y dy = 2x dx
@runger723 it became like one of those which we did earlier
When I took cal1, I stuck at this problem since I tried to figure out the method to find out int of some tricky thing. My classmate gave me this method: try derivative of some simple thing to get the tricky one.
Like this, we know (e^y )' = e^y, and int (e^y) = e^y also how about e^(-y)? play around with -e^(-y) :)
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