Question from Riemann integral. Need help.
the riemann integral is the sum of the areas under the curve, therefore, if the functions has negative values, we will also get negative areas, that in the total sum in the interval from a to b, this can be positive, negative or zero, and it's not necessary that the functions f is 0 for every x in [a, b]
for example, \(f(x) = sin(x)\) in the interval \([0, 2\pi]\), we have \[\int_{0}^{2\pi} sin(x) dx = 0\]
we have integral over a to b, |f(x)|dx=0 in [a,b]
@M4thM1nd
Oh i didn't see the | |. From the definition of modulus: |f(x)| = f(x), if f(x) > 0 |f(x)| = -f(x), if f(x) < 0
@ganeshie8
@Alchemista
so... \[\int_{a}^{b} \left| f(x) \right|dx = -\int_{a}^{c} f(x)dx + \int_{c}^{b} f(x)dx\], where f(x) is negative in [a, c] and f(x) is positive in [c,b]
that means that the only way this integral be 0 is if f(x) = 0 in [a, b]
we know that \[|\int\limits_{a}^{b}f dx| \le \int\limits_{a}^{b}|f|dx\]
@M4thM1nd I don't get the reasoning properly, kindly explain.
both the answers are no..
however thanks, you tried to help.@M4thM1nd
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