Question

Find the specific solution of the differential equation dy /dx = 4y/x^2 with condition y(−4) = 1.

a: y =- 1 - 4/ x
b: y =-e^(1/x)
c: y=e^(-4/x)
d: None of these

Answer 1

@rational can u plz help? :)

Answer 2

@nirmalnema

Answer 3

@apoorvk

Answer 4

dy /dx = 4y/x^2
dy/4y=dx/x^2
now u can easily int both the side.1!

Answer 5

so what would i get as an answer? :)

Answer 6

first u try ..then i will help u.

Answer 7

i dont know how to integrate both sides :(

Answer 8

simply int one by one LHS and RHS

Answer 9

so would it be: 4y/x^2 & i have to integrate that?

Answer 10

dy/4y=dx/x^2 int this.

Answer 11

would it be: y(x) = c1 e^(-4/x)

Answer 12

http://www.wolframalpha.com/input/?i=+dy%2F4y%3Ddx%2Fx%5E2+integrate

Answer 13

yup..!!

Answer 14

so i think its C, y = e^(-4/x)

Answer 15

yaa..!!

Answer 16

thank u!!!!!!!! :)