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Mathematics 15 Online
OpenStudy (aaronandyson):

Help.

OpenStudy (aaronandyson):

\[3x - 5 \le x + 3 < 5x - 9\] x belongs to real numbers.

OpenStudy (igreen):

Subtract 3 to all sides

OpenStudy (igreen):

\(3x-5 -3 \le x \le 5x-9-3\)

OpenStudy (igreen):

Simplify, can you do that?

OpenStudy (igreen):

@AaronAndyson

OpenStudy (aaronandyson):

\[3x - 8 \le x \le 5x - 12\]

OpenStudy (aaronandyson):

@rvc

OpenStudy (aaronandyson):

@ilovewolf

OpenStudy (aaronandyson):

@bibby @ilovewolf

OpenStudy (aaronandyson):

@dtan5457

OpenStudy (ilovewolf):

@Directrix

Directrix (directrix):

The thread posts leave off with: 3x -8 ≤ x < 5x - 12 --> the second inequality symbol is < and not ≤ as written above

OpenStudy (aaronandyson):

What does that ? mean

OpenStudy (aaronandyson):

\[3x - 8 \le x \le 5x - 12\]

OpenStudy (aaronandyson):

@Directrix

Directrix (directrix):

Correct the symbol in your work. See attachment.

OpenStudy (aaronandyson):

ok so now?

OpenStudy (aaronandyson):

\[3x - 8 \le x \le 5x - 12\]

Directrix (directrix):

In the problem you posted, you wrote "less than" but now you write less than or equal to. According to what you posted as the problem. This is where you should be now: --------------------------- 3x -8 ≤ x < 5x - 12 --------------------------

Directrix (directrix):

3x -8 ≤ x < 5x - 12 means the following: 3x - 8 ≤ x AND x < 5x - 12 3x -x ≤ 8 AND x - 5x < -12 2x ≤ 8 AND -4x < -12 x ≤ 4 AND x > 3

Directrix (directrix):

Putting these together to get the answer: x ≤ 4 AND x > 3 becomes 3 < x ≤ 4 ---> Solution to Compound Inequality

Directrix (directrix):

@AaronAndyson

Directrix (directrix):

You are welcome.

OpenStudy (aaronandyson):

THANKS!!!!!!!!!!!!!

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