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Mathematics 16 Online
OpenStudy (anonymous):

uniform convergence

OpenStudy (anonymous):

OpenStudy (anonymous):

@bibby

OpenStudy (anonymous):

I'm thinking you can use Dirichlet's test (see here: https://proofwiki.org/wiki/Dirichlet%27s_Test_for_Uniform_Convergence ) with \[\sum_{n=1}^\infty \frac{(-1)^{n-1}}{n+x^2}=\sum_{n=1}^\infty \underbrace{\frac{(-1)^{n-1}}{n}}_{a_n}\underbrace{\frac{1}{1+\frac{x^2}{n}}}_{b_n}\] If I recall correctly, \(a_n\to\ln2\), so its partial sums must be bounded. \(b_n\) seems to be monotonic, and as \(n\to\infty\) you have \(b_n(x)\to1\) (whether this is uniform, I'm not sure).

OpenStudy (anonymous):

No.. b_n(x) must tend to 0.@SithsAndGiggles

OpenStudy (anonymous):

@SithsAndGiggles

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@SithsAndGiggles I used Dirichlet's test too. however I took a_n=(-1)^n and b_n the rest./ Thanks for the idea

OpenStudy (anonymous):

Yeah sorry, I misread the conditions in the link :/

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