Question

Glider A, traveling at 10 m/s on an air track, collides elastically with glider B traveling at 8.0 m/s in the same direction. The gliders are of equal mass. The final speed of glider B is
(a) 8.4 m/s
(b) 10 m/s
(c) 8.0 m/s
(d) 4.0 m/s
(e) 12 m/s
The answer is B, but I'm not sure why.

Answer 1

Please you have to apply the conservation momentum law and the conservation kinetic energy law

Answer 2

Let m1=m2=m

Answer 3

According to conservation of momentum
m1*u1+m2*u2=m1*v1+m2*v2
m*10+m*8=m*v1+m*v2
18m=m1*v1+m2*v2.........(1)

Answer 4

Now u hv to use the law of conservation of kinetic energy
(1/2)*m1*u1^2+(1/2)*m2*u2^2=(1/2)*m1*v1^2+(1/2)*m2*v2^2

Answer 5

50m+32m=.5m*v1^2+.5*m*v2^2............(2)

Answer 6

Frm equation (1) and (2)
Find v1=?
v2=?

Answer 7

Response plz!!!!