I need serious help on this packet, because I kind of get it, but at the same time I don't really understand it. I answered some of the questions which need to be checked for correctness and the ones that I don't have answers for, I need help on those. *If you need to explain each problem, so I have a better idea of what they are talking about on the packet.* *My Answers are in a PDF File*
I think you got the answer, right? on the previous one
@satellite73 please, explain,
@satellite73 for which number
Agree, that's what he needs
ignore me
first page is all correct, ignore my previous comment
for 5) I think on (-1,0) f(x)<x
second page, i assume the \(f\) is the \(f\) on the first page right?
on [0,2], f(x) =x, hence it does not satisfy f(x) >x, take it off
on [3,4], f(x) <x
on (4,5] f(x) =x, get rid off on (5,6) f(x) < x, get rid off the interval hence, just [-6,-3) and [-2,-1) are the intervals in which f(x) >x
for 7) only -6 is the point when f(x) gets global minimum
f(-2) = 0, it's not minimum
f(0) is not the global minimum because (0, -2) is not on the graph.
is the first page correct or not
10b) f(-6) is minimum, hence at this point g(x) = f(-x) = f(6) = 5, hence it is maximum value of g
I checked one by one from 1 upto 10 now, why do you ask for the first page or the second page?
to do 11, you need do 10c, show me the graph
12 is the same, need graph
What's wrong with #5?
ok, 5) asks you find where f(x) > x, right? at x =-1, f(x) =-1, hence f(x) \(\color{red}{=}\)x, not > x, ok?
a little bit up for x, for example, if x = -0.5, f(-0.5 ) = -1.5, hence f(x) \(\color{red}{<}\) x, it is not f(x) > x got what I mean?
Join our real-time social learning platform and learn together with your friends!