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Mathematics 11 Online
OpenStudy (firejay5):

I need serious help on this packet, because I kind of get it, but at the same time I don't really understand it. I answered some of the questions which need to be checked for correctness and the ones that I don't have answers for, I need help on those. *If you need to explain each problem, so I have a better idea of what they are talking about on the packet.* *My Answers are in a PDF File*

OpenStudy (firejay5):

OpenStudy (loser66):

I think you got the answer, right? on the previous one

OpenStudy (loser66):

@satellite73 please, explain,

OpenStudy (firejay5):

@satellite73 for which number

OpenStudy (loser66):

Agree, that's what he needs

OpenStudy (anonymous):

ignore me

OpenStudy (anonymous):

first page is all correct, ignore my previous comment

OpenStudy (loser66):

for 5) I think on (-1,0) f(x)<x

OpenStudy (anonymous):

second page, i assume the \(f\) is the \(f\) on the first page right?

OpenStudy (loser66):

on [0,2], f(x) =x, hence it does not satisfy f(x) >x, take it off

OpenStudy (loser66):

on [3,4], f(x) <x

OpenStudy (loser66):

on (4,5] f(x) =x, get rid off on (5,6) f(x) < x, get rid off the interval hence, just [-6,-3) and [-2,-1) are the intervals in which f(x) >x

OpenStudy (loser66):

for 7) only -6 is the point when f(x) gets global minimum

OpenStudy (loser66):

f(-2) = 0, it's not minimum

OpenStudy (loser66):

f(0) is not the global minimum because (0, -2) is not on the graph.

OpenStudy (firejay5):

is the first page correct or not

OpenStudy (loser66):

10b) f(-6) is minimum, hence at this point g(x) = f(-x) = f(6) = 5, hence it is maximum value of g

OpenStudy (loser66):

I checked one by one from 1 upto 10 now, why do you ask for the first page or the second page?

OpenStudy (loser66):

to do 11, you need do 10c, show me the graph

OpenStudy (loser66):

12 is the same, need graph

OpenStudy (firejay5):

What's wrong with #5?

OpenStudy (loser66):

ok, 5) asks you find where f(x) > x, right? at x =-1, f(x) =-1, hence f(x) \(\color{red}{=}\)x, not > x, ok?

OpenStudy (loser66):

a little bit up for x, for example, if x = -0.5, f(-0.5 ) = -1.5, hence f(x) \(\color{red}{<}\) x, it is not f(x) > x got what I mean?

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