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Mathematics 9 Online
OpenStudy (anonymous):

HELP WITH THIS COLLEGE ALGEBRA PROBLEM ASAP!?!?!?

OpenStudy (anonymous):

(1/2 + sqrt 3/(2) i)^2

OpenStudy (anonymous):

\[(\frac{1}{2}+\frac{\sqrt3}{2}i)^2\] right?

OpenStudy (anonymous):

Yes, that's it. @satellite73

OpenStudy (anonymous):

if you knew trig you can do it in your head, but in this case i would just multiply out \[(\frac{1}{2}+\frac{\sqrt3}{2}i)(\frac{1}{2}+\frac{\sqrt3}{2}i)\]

OpenStudy (jhannybean):

\[(a+b)^2 = a^2+2ab+b^2 ~,~ i^2 = -1\]

OpenStudy (anonymous):

you can even use the so called "foil" method, or you can use \\[(a+bi)(a+bi)=a^2-b^2+2abi\]

OpenStudy (anonymous):

in your case \(a=\frac{1}{2}\) adn \(b=\frac{\sqrt3}{2}\)

OpenStudy (anonymous):

if this is not clear, let me know

OpenStudy (jhannybean):

oh and \(i=\sqrt{-1}\)

OpenStudy (anonymous):

so would the answer be the same as the problem but a negative in the front and dropping the ^2?

OpenStudy (anonymous):

uh yea actually

OpenStudy (anonymous):

if by which you mean the answer is \[-\frac{1}{2}+\frac{\sqrt3}{2}i\] then you are correct

OpenStudy (anonymous):

awesome, that's what my book says. Thank you!!

OpenStudy (anonymous):

This idiot keeps leaving open old questions so that everybody will be too distracted to answer the new important ones.

Directrix (directrix):

@OpiGeode Spamming is a violation of the OpenStudy CoC. http://openstudy.com/code-of-conduct

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