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simplify this expression cos(theta, the 0with a line through it)/tan(theta)cot(theta) A)sin(theta) B)cos(theta) C)csc(theta) D)sec(theta)
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lol 0 with a line \(\theta\) right?
the variable is unimportant
yes
rewrite all in terms of sine and cosine
i didn't know how to put it in but that was the symbol
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no problem lets dispense with the trig all together
call \(\sin(\theta)=b, \cos(\theta)=a\) then this is the same as \[a\times \frac{b}{a}\times \frac{a}{b}\]
or even easier, know that cotangent is the reciprocal of tangent so \[\tan(x)\cot(x)=1\]
i'm a little lost
lets go slow then
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so it could be cos*sin/cos*cos/sin?
yes it would
and when you are done cancelling you are left only with \(\cos(\theta)\)
ohhh ok
ty
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yw
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