How do you put this in point-slope form? through (4,1), parallel to 2x+5y=10
y-1 = -2/5 (x-4)
Hint: please note that the equation of the given line, namely: \[2x + 5y = 10\] can be rewritten as below: \[y = - \frac{2}{5}x + 2\]
so, waht is its slope
2/5 @Michele_Laino
no, please it is -2/5
Yeah I just wrote it how you had it in the equation, it was a positive but my mistake. So now that I have the slope, all I do is plug it into the formula?
now, keep in mind that parallel lines have the same slope, so the slope of requested line is m= -2/5, furthermore, you have to apply this equation: \[y - {y_0} = m(x - {x_0})\] where: \[\left( {{x_0},{y_0}} \right) = \left( {4,1} \right)\]
so, please substitute those value of x_0, y_0 and m into the above equation
what do you get?
I'm kinda confused with how I'm multiplying my fraction. This is how I set my problem up: y-1=-2/5(x-4) distributed: y-1=-2/5x+ ? I know its -2/5 times 4/1. Then I make the denominators alike = -2/5 times 20/5 Am I doing something wrong?
your first step is correct your second step is: \[y - 1 = - \frac{2}{5}x + \frac{8}{5}\] since: \[\left( { - \frac{2}{5}} \right) \cdot \left( { - 4} \right) = \frac{8}{5}\]
Oh I get it now Michele. I was supposed to multiply without like denominators, just straight across. My teacher told me this but I didn't get it
So it's gonna be \[y-1=-\frac{ 2 }{ 5 }x+\frac{ 8 }{ 5 }\]
that's right!
But how do you subtract 1 from \[\frac{ 8 }{ 5 }\]
I mean add 1
please note that you have to add 1 to both sides of your last equation, namely: \[y - 1 + 1 = - \frac{2}{5}x + \frac{8}{5} + 1\] furthermore, we have this: \[\frac{8}{5} + 1 = \frac{{8 + 1 \cdot 5}}{5} = ...?\]
\[\frac{ 45 }{ 5 }\]
no, please you have to compute the multiplication first
Oh yeah you right, \[\frac{ 8+(1\times5) }{ 5 } =\frac{ 8+5 }{ 5 } = \frac{ 13 }{ 5 } =2 \frac{ 3 }{ 5 }\]
perfect! well done!
Why did you multiply the top by 5?
since the denominator of 1 is 1, so you have to add this fractions: \[\frac{8}{5} + \frac{1}{1}\] now the least common multiple between 5 and 1 is 5, so the denominator of your result is 5: \[\frac{8}{5} + \frac{1}{1} = \frac{?}{5}\] now, since 5:5= 1, then you have to multiply 8 by 1, and since 5:1=5, then you have to multiply 1 by 5, like this: \[\frac{8}{5} + \frac{1}{1} = \frac{{\left( {8 \times 1} \right) + \left( {1 \times 5} \right)}}{5} = \frac{{8 + 5}}{5}\]
So i'ts kinda like you cross multiply without the equal sign in the middle then. Do you always do this for problems like these?
yes!
Okay, thank you Michele, you help me get it :)
thank you! :)
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