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Physics 13 Online
OpenStudy (mintiruki):

I know the answer to this Electrostatics question, but how do I get there? Here is the question with the answer: "A + 4.75 microC and a -3.55 microC charge are placed 18.5 cm apart. Where can a third charge be placed so that it experiences no net force?" Answer: .116 m (if my source is accurate) @abhisar Someone recommended me to you, can you help me??

OpenStudy (mintiruki):

OpenStudy (abhisar):

Give me a sec.

OpenStudy (abhisar):

Ok, sorry I was helping someone else...

OpenStudy (abhisar):

So, for this question I'll give you few examples on how to solve similar problems.

OpenStudy (abhisar):

These are called equilibrium questions and we are trying to find the Null Point which is a point where the net force is zero.

OpenStudy (abhisar):

There are two cases Case 1 When both the charges given are similar i.e either both are positive or both are negative. In this case we use the following formula, \(\sf \huge \boxed{ x = \frac{\sqrt{q_1}}{\sqrt{q_1}+\sqrt{q_2}}}\times r\)

OpenStudy (abhisar):

Example: Two charges are 4C and 9C kept at 30 m from each other. Find a place where third charge should kept so that it receives 0 net force. Solution: Here. \(\sf q_1\) will be the smaller charge and \(\sf q_2\) will be the bigger charge. r is the distance between the two charge. Plugging in the values we get, \(\sf \huge \frac{2}{2+3}\times 30\) = 12 m. Now this means we should keep the third charge 12 m away from the 4C charge in the direction of 4C charge.

OpenStudy (abhisar):

Similarly, In case II when the given charges are unlike you use the following formula. \(\boxed{ \sf \huge x = \frac{\sqrt{q_1}}{\sqrt{q_1}-\sqrt{q_2}}\times r}\)

OpenStudy (abhisar):

Your original question is similar to CaseII.

OpenStudy (mintiruki):

Okay, actually I think I figured it out (was not sure at first). Thank you very much :)!

OpenStudy (abhisar):

Example, Two charges 9C and -4C are placed 10 m apart. Find where should a third charge be placed so that it experiences a 0 net force. Solution: \(\huge \mathcal{ \frac{2}{2-3}\times 10=-20}\) This means the third charge should be kept at a distance of 20m from the charge 4C in direction of 4C charge.

OpenStudy (abhisar):

Okay, actually I think I figured it out (was not sure at first). Thank you very much :)!

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