Question

Guys can someone help me?

Answer 1

An equation is shown below:

\[\frac{ 3 }{ 2 }x +\frac{ 7 }{ 2 }=2x\]

What is the solution to the equation?

Answer 2

@pooja195

Answer 3

Put all the x's on on side. Since 2x is already by itself I would move (3/2)x

Answer 4

What will that turn the equation into?

Answer 5

Subtract (2/3)x from both did

Answer 6

\[\frac{ 7 }{ 2 }=2x+\frac{ 3 }{ 2 }x\]

Answer 7

no it was positive (3/2)x on the other side so you would want to subtract it from both sides

Answer 8

So it would look like \[7/2 = 2x-(3/2)x\]

Answer 9

ohh ok

Answer 10

So what is 2-(3/2)?

Answer 11

1?

Answer 12

not quite when subtracting fractions remember to find the common denominator. So 2/1 and 3/2 have a common denominator of 2. So it will essentially be (4/2) - (3/2) = 4-3/2. Which is 1/2

Answer 13

So on the right side you know have 1/2x

Answer 14

oh ok

Answer 15

*now

Answer 16

wouldn't you have to divide both sides by 1/2?

Answer 17

Yes and that gives you?

Answer 18

1 3/4 = x is what I got

Answer 19

@TheDream are you there?

Answer 20

not quite remember that dividing by 1/2 is the same as multiplying by 2. So 7/2 *2 equals what?

Answer 21

I got 7

Answer 22

Yep that looks about right good job.

Answer 23

but that's not an answer choice....

Answer 24

really what are the choices?

Answer 25

x = 1 x = 3 x = 5 x = 8

Answer 26

did you write the question correctly?

Answer 27

yess

Answer 28

oh wait... no I didnt

Answer 29

because 7 is definitely the solution to that equation

Answer 30

the 2 is to the x power

Answer 31

so it is \[2^x \] not \[2x\]

Answer 32

and everything else is the same?

Answer 33

yep

Answer 34

\[\frac{ 3 }{ 2 }x+\frac{ 7 }{ 2 }=2^{x}\]

Answer 35

kk just a minute. Way different problem now I know the answer but I want to find a good solution

Answer 36

Lol ok thank you so much for your help btw :D

Answer 37

What kind of class is this for?

Answer 38

Algebra 1 Honors

Answer 39

I can't seem to solve it analytically but I did find the answer by graphing the function. Or simply by just plugging in the different x's into the equation.

Answer 40

Try to ask someone else maybe there is a simple solution I am missing but this seems like an extremely messy problem.

Answer 41

lol thank you anyway :D