Question

For an object whose velocity in ft/sec is given by v(t) = −3t^2 + 5, what is its displacement, in feet, on the interval t = 0 to t = 2 secs?

a) 6.607
b)2
c)−2.303
d)2.303

Answer 1

@pooja195 @ganeshie8 @Luigi0210 @Abhisar @Compassionate @Destinymasha @Directrix

Answer 2

@Kainui

Answer 3

@Zale101

Answer 4

first derivative

Answer 5

Change in x(displacement) = is the integral of velocity

Answer 6

So integrate from 0 to 2 that function for velocity.

Answer 7

so would it be A, 6.607

Answer 8

What is the \[\int\limits_{0}^{2} -3t^2+5 dt\]