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Mathematics 7 Online
OpenStudy (anonymous):

under what condition is average velocity equal to the average of the objects initial and final velocity? I feel like this would be impossible because average velocity is delta x/ delta t and the average of the intial and and final velocity would be the velocities added together and divided by 2 ? I have no idea I'm ver confused

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

i guess if the velocity was zero it would work right?

OpenStudy (misty1212):

or for that matter, any constant velocity

OpenStudy (anonymous):

that's what I thought first and it's what I answered on my quiz but I got it wrong. here are the choices I was given: a. the acceleration must be constantly changing b. the acceleration must be constant c. this can only occur when there is no acceleration d. this is impossible

OpenStudy (anonymous):

I answered c but It was wrong

OpenStudy (misty1212):

i would go with B

OpenStudy (misty1212):

oops no sorry

OpenStudy (misty1212):

acceleration constant means velocity is changing no acceleration means velocity is constant

OpenStudy (misty1212):

oh C was wrong?

OpenStudy (anonymous):

mhmm

OpenStudy (misty1212):

and the average of the intial and and final velocity would be the velocities added together and divided by 2 ? is incorrect

OpenStudy (anonymous):

then what is it and how is it different from the average velocity ?

OpenStudy (adi3):

sup

OpenStudy (misty1212):

that is the average of two numbers

OpenStudy (misty1212):

the average velocity is how far you travel divided by how long it takes

OpenStudy (adi3):

what r the options

OpenStudy (misty1212):

like if you drive 100 miles in two hours, average velocity is 50 mph

OpenStudy (adi3):

what r the options

OpenStudy (anonymous):

yeah I get average velocity what about average of the initial and the final ?

OpenStudy (anonymous):

final- initial / time take ?

OpenStudy (misty1212):

actually i should be quiet, because i have no idea what "the average of the objects initial and final velocity?"

OpenStudy (anonymous):

haha it's okay thanks for trying

OpenStudy (anonymous):

@Adi3 I have the options above

OpenStudy (misty1212):

does it mean the "average OF the velocities"? like if the initial velocity is 20 and the final is 10 then the average is 15? makes no real sense to me

OpenStudy (adi3):

alright, I saw the options.

OpenStudy (anonymous):

why not?

OpenStudy (anonymous):

@ganeshie8

OpenStudy (adi3):

I think its imposible because as @1234abdc explained above.

OpenStudy (adi3):

I would go for D

OpenStudy (anonymous):

But I'm not sure about that explanation . You guys could give me theories it's okay

OpenStudy (adi3):

go for D

OpenStudy (anonymous):

but I need to know why

OpenStudy (solomonzelman):

wouldn't it work every time?

OpenStudy (solomonzelman):

both of them are the slope of the secant (between the 2 endpoints - i.e. your first and last velocities)

OpenStudy (solomonzelman):

(That is the first thing that comes to my mind. I can be wrong though, b/c I am not very good at math. )

OpenStudy (thomas5267):

b is the correct answer. Don't know how to explain it though.

OpenStudy (thomas5267):

Under constant acceleration, the velocity-time graph will be a straight line. For example, if an object accelerates from rest at 5 \(\text{m s}^{-2}\), after one second its velocity will be 5 \(\text{m s}^{-1}\), after two seconds its velocity will be 10 \(\text{m s}^{-1}\), and after three seconds its velocity will be 15 \(\text{m s}^{-1}\), and so on. The graph would be a straight line.

OpenStudy (phi):

graph velocity as a function of time|dw:1424619391710:dw|

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