The ΔH of the reaction below is -575.13 kJ. Is this reaction spontaneous? 2ZnS + 3O2 + C → 2SO2 + 2Zn + CO2 A. It depends on the temperature because the ΔH of the reaction is negative and the ΔS is positive. B. It is because the ΔH of the reaction is negative. C. It depends on the temperature because the ΔH of the reaction is negative and the ΔS is negative. D. It is not because the ΔH of the reaction is negative.
Did you calculate delta s already?
If s>0, then yeah, it's likely A.
All I know is that if h<0 and s>0, it's more than likely spontaneous. You can wait for other opinions, though.
Okay, let me know if it was right
negative value for delta H indicates that reaction is exothermic in other words according to entropy (thermodynamics) this reaction is energetically favorable
energetically favorable means spontaneous
@Somy so I'm right?
it's A?
S has to be positive though but well the question is telling you about delta H only
im between A & B
but im more positive about B because your question gave delta H as info
Hmmm ok... thank you
no problem
@Somy It was wrong..the answer is C
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