Indefinite integral problem with trig functions using substitution: integral of 5 * sec^2(5x) * tan^5(5x) dx
u = tan(5x), du = 5(sec(5x))^2 dx
\(\large\color{slate}{\displaystyle 5\int\limits_{~}^{~}\sec^2(5x)\times \tan^5(5x)~dx}\) this?
then yes, u=tan(5x) as was suggested, because the derivative of tan(5x) is 5sec^2(5x) (sitting inside there)
yes though the five is inside the integral, though that shouldn't matter
yes, so your derivative of "u" is sitting inside the integral for you already
I see how that works. What am I left with after I use that tan(5x)? tan^4(5x)?
no
u^5
\(\large\color{slate}{\displaystyle\int\limits_{~}^{~}5\sec^2x\tan^5(5x)~dx}\) \(\large\color{slate}{\displaystyle\int\limits_{~}^{~}5(\sec~x)^2~(\tan~5x)^5~dx}\) \(\large\color{blue}{\displaystyle u=\tan ~5x}\) \(\large\color{green}{\displaystyle du=5(\sec ~5x)^2~dx}\) \(\large\color{slate}{\displaystyle\int\limits_{~}^{~}\color{green}{5(\sec~x)^2}~(\color{blue}{\tan~5x})^5~\color{green}{dx} }\) \(\large\color{slate}{\displaystyle\int\limits_{~}^{~}(\color{blue}{u})^5~\color{green}{du} }\)
and the \(\large\color{green}{ 5(\sec~5x)^2 }\) went away with \(\large\color{green}{ dx }\) TO BE REPLACED BY \(\large\color{green}{ du }\)
Oh Okay that makes sense! I always forget the laws for trig functions. Okay can I finish this and see if we got the same answer?
yes, apply the power rule, and then sub the tan(5x) back for "u" as you are done.
So it should be 1/6 * tan^6(5x)?
yes, with one more thing.... (you left something out)
+ ... ?
+ C
Yup
uggggggghhhhh I always forget that one after a long problem
\(\large\color{black}{ \displaystyle \frac{\tan^6(5x)}{6} ~+C }\)
I would take almost all points off for leaving out +C
because when you don't write +C you only include 1 possible answer out of the infinite number of answers there are.
Good integration, but +C is very important, because not only \(\large\color{black}{ \displaystyle \frac{\tan^6(5x)}{6} ~ }\), but also ANY \(\large\color{black}{ \displaystyle \frac{\tan^6(5x)}{6} ~+C }\) will have a slope of \(\large\color{black}{ \displaystyle 5\sec^2(5x)\tan^5(5x) }\).
(good job though...) yw
Thanks Solomon. Your name fits you!
You mean it as the King Solomon? Tnx for the complement, I will take it:D
absolutely!
You too will surely get there... you are moving very quickly in your math latter.
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