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OpenStudy (ageta):
Write the following linear equations in slope-intercept form
OpenStudy (ageta):
2x-4y=12
OpenStudy (solomonzelman):
\(\large\color{slate}{ \displaystyle y=mx+b}\) is the slope intercept form.
OpenStudy (solomonzelman):
you need to rearrange it. Solve for y.
OpenStudy (ageta):
go on
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OpenStudy (solomonzelman):
\(\large\color{slate}{ \displaystyle 2x-4y=12}\)
you need to isolate the y.
1. subtract 2x from sides
2. divide each term in the equation by -4.
if you do it correctly, you are done.
OpenStudy (anonymous):
correct ^^^ :), so what would you get
OpenStudy (ageta):
y=-2/4x+3
OpenStudy (solomonzelman):
close
OpenStudy (solomonzelman):
\(\large\color{slate}{ \displaystyle -4y=-2x+12}\) is what you get when you subtract x from both sides.
when you divide each term by -4,
\(\large\color{slate}{ \displaystyle \frac{-4y}{-4}= \frac{-2x}{-4}+ \frac{12}{-4}}\)
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OpenStudy (solomonzelman):
please try one more time... (you got the numbers, but made some mistakes on signs)
OpenStudy (ageta):
y=2/4x +8
OpenStudy (ageta):
is this right
OpenStudy (solomonzelman):
12/(-4) = -3
OpenStudy (solomonzelman):
\(\large\color{slate}{ \displaystyle y=\frac{2}{4}x-3 }\)
and then one more thing you can do....
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OpenStudy (ageta):
oh.. i got it now
OpenStudy (ageta):
tnxs
OpenStudy (solomonzelman):
you can reduce the 2/4
OpenStudy (solomonzelman):
2 and 4 can both be divided by 2
OpenStudy (ageta):
1/2
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